Cách làm cho bạn:
Ta có:
B=$\frac{8^{5}+(−2)^{12}}{2^{15}+64^{3}}$
$=\frac{(2^{3})^{5}+2^{12}}{2^{}15+(2^{6})^{3}}$
$=\frac{2^{15}+2^{12}}{2^{15}+2^{18}}$
=$\frac{2^{12}.(2^{3}+1)}{2^{15}.(1+2^{3})}$
=$\frac{1}{2^{3}}$
=$\frac{1}{8}$
Bài 2: Tính giá trị biểu thức sau:
$B=\frac{8^{5}+(−2)^{12}}{2^{15}+64^{3}}$
Ta có:
B=$\frac{8^{5}+(−2)^{12}}{2^{15}+64^{3}}$
$=\frac{(2^{3})^{5}+2^{12}}{2^{}15+(2^{6})^{3}}$
$=\frac{2^{15}+2^{12}}{2^{15}+2^{18}}$
=$\frac{2^{12}.(2^{3}+1)}{2^{15}.(1+2^{3})}$
=$\frac{1}{2^{3}}$
=$\frac{1}{8}$
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