Cách làm cho bạn:
Ta có:$961= 31^{2}$ => $\sqrt{961}$ = 31
1024= $32^{2}$ =>$\sqrt{1024}$=32
a= $\sqrt{961}+\frac{1}{\sqrt{962}}$ = $31$+$\frac{1}{\sqrt{962}}$
b= $\sqrt{1024}+\frac{1}{\sqrt{1023}}-1$= $32$+$\frac{1}{\sqrt{1023}}$-$1$ = $31$+$\frac{1}{\sqrt{1023}}$
Vì $\sqrt{962}<\sqrt{1023}$ => $\frac{1}{\sqrt{962}}$>$\frac{1}{\sqrt{1023}}$
=> $31$+$\frac{1}{\sqrt{962}}$ >$31$+$\frac{1}{\sqrt{1023}}$
=> a>b
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