Cách làm cho bạn:
a) (-$\frac{20x}{3y^{2}}$) : (-$\frac{4x^{3}}{5y}$) = ($\frac{-20x}{3y^{2}}$).($\frac{-5y}{4x^{3}}$) = $\frac{(-20x)(-5y)}{3y^{2}.4x^{3}}$ = $\frac{25}{3x^{2}y}$;
b) $\frac{4x + 12}{(x + 4)^{2}}$ : $\frac{3(x + 3)}{x + 4}$ = $\frac{4(x + 3)}{(x + 4)^{2}}$.$\frac{x + 4}{3(x + 3)}$ = $\frac{4}{3(x + 4)}$.
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