Cách làm cho bạn:
Xét hiệu hai vế:
\(\frac{a^2}{a+b}-\frac{b^2}{a+b}+\frac{b^2}{b+c}-\frac{c^2}{b+c}+\frac{c^2}{c+a}-\frac{a^2}{c+a}\)
\(=\frac{a^2-b^2}{a+b}+\frac{b^2-c^2}{b+c}+\frac{c^2-a^2}{c+a}\)
\(=\frac{(a-b)(a+b)}{a+b}+\frac{(b-c)(b+c)}{b+c}+\frac{(c-a)(c+a)}{c+a}\)
\(=a-b+b-c+c-a=0\)
Vậy \({{{a^2}} \over {a + b}} + {{{b^2}} \over {b + c}} + {{{c^2}} \over {c + a}} = {{{b^2}} \over {a + b}} + {{{c^2}} \over {b + c}} + {{{a^2}} \over {c + a}}\)
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