a)     \(x.{3 \over 7} = {2 \over 3}\)

\(x=\frac{2}{3} \div \frac{3}{7}\)

\(x=\frac{2}{3} .\frac{7}{3} \)

\(x=\frac{14}{9}\)

b)    \(x \div {8 \over {11}} = {{11} \over 3}\)

\(x=\frac{11}{3}.\frac{8}{11}\)

\(x=\frac{8}{3}\)

c)     \({2 \over 5} \div x = {{ - 1} \over 4}\)

\(x=\frac{2}{5} \div \frac{-1}{4}\)

\(x=\frac{2}{5} .(-4)\)

\(x=\frac{-8}{5}\)

d)    \({4 \over 7}.x - {2 \over 3} = {1 \over 5}\)

\({4 \over 7}.x=\frac{1}{5}+\frac{2}{3}\)

\({4 \over 7}.x=\frac{13}{15}\)

\(x=\frac{13}{15} \div \frac{4}{7}\)

\(x=\frac{91}{60}\)

e)     \({2 \over 9} - {7 \over 8}.x = {1 \over 3}\)

\({7 \over 8}.x=\frac{2}{9} -\frac{1}{3}\)

\({7 \over 8}.x=\frac{-1}{9}\)

\(x=\frac{-1}{9} \div \frac{7}{8}\)

\(x=\frac{-8}{63}\)

g)    \({4 \over 5} + {5 \over 7} \div x = {1 \over 6}\)

\({5 \over 7} \div x=\frac{1}{6} -\frac{4}{5}\)

\({5 \over 7} \div x=\frac{-19}{30}\)

\(x=\frac{5}{7} \div \frac{-19}{30}\)

\(x=\frac{-150}{133}\)