Cách làm cho bạn:
- \(\widehat{BOI}= \frac{1}{4}\widehat{ AOB}=\frac{1}{4}60^{0}=15^{0}\)
Vậy $\widehat{BOI}=15^{\circ}$
- Do tia $OI$ nằm giũa hai tia $OA, OB$ nên \(\widehat{AOI}+\widehat{ BOI}=\widehat{AOB}\)
=> $\widehat{AOI}=\widehat{AOB}-\widehat{ BOI}=60^{\circ}-15^{\circ}=45^{\circ}$
Vậy $\widehat{AOI}=45^{\circ}$
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